Using formulas En = -13.6 × (Z²/n²) eV (converted to Joules) and rn = a₀(n²/Z). For He+ (Z=2), E = -13.6 * 4 * 1.6 * 10^-19 = -8.72 * 10^-18 J. For Li2+ (Z=3), E = -13.6 * 9 * 1.6 * 10^-19 = -19.62 * 10^-18 J.
Q51mcq
Which of the following are paramagnetic? A. [NiCl4]²⁻ B. Ni(CO)₄ C. [Ni(CN)₄]²⁻ D. [Ni(H₂O)₆]²⁺ E. Ni(PPh₃)₄
a.
A and C only
b.
B and E only
c.
A and D only
Correct Answer
d.
A, D and E only
Step-by-Step AI Explanation
Verified Method
[NiCl₄]²⁻ (sp³) is paramagnetic (2 unpaired e⁻). Ni(CO)₄, [Ni(CN)₄]²⁻, and Ni(PPh₃)₄ are diamagnetic. [Ni(H₂O)₆]²⁺ (sp³d²) is paramagnetic (2 unpaired e⁻).
Q52mcq
Given below are two statements: Statement I: Like nitrogen that can form ammonia, arsenic can form arsine. Statement II: Antimony cannot form antimony pentoxide.
a.
Both Statement I and Statement II are correct.
b.
Both Statement I and Statement II are incorrect.
c.
Statement I is correct but Statement II is incorrect.
Correct Answer
d.
Statement I is incorrect but Statement II is correct.
Step-by-Step AI Explanation
Verified Method
Statement I is correct (AsH₃ is arsine). Statement II is incorrect because Antimony forms Sb₂O₅ (antimony pentoxide).
Q53mcq
Which among the following electronic configurations belong to main group elements? A. [Ne]3s¹ B. [Ar]3d³4s² C. [Kr]4d¹⁰5s²5p⁵ D. [Ar]3d¹⁰4s¹ E. [Rn]5f⁰6d²7s²
a.
B and E only
b.
A and C only
Correct Answer
c.
D and E only
d.
A, C and D only
Step-by-Step AI Explanation
Verified Method
Main group elements have s or p orbitals as the valence shell (s-block and p-block). A ([Ne]3s¹) and C ([Kr]4d¹⁰5s²5p⁵) are main group elements. B, D, and E are transition or inner-transition metals.
Q54mcq
Dalton's Atomic theory could not explain which of the following?
a.
Law of conservation of mass
b.
Law of constant proportion
c.
Law of multiple proportion
d.
Law of gaseous volume
Correct Answer
Step-by-Step AI Explanation
Verified Method
Dalton's atomic theory does not account for Gay-Lussac's Law of Gaseous Volumes, which relates to the combining ratios of gases by volume.
Q55mcq
Consider the following compounds: KO₂, H₂O₂ and H₂SO₄. The oxidation states of the underlined elements in them are, respectively,
a.
+1, –1, and +6
Correct Answer
b.
+2, –2, and +6
c.
+1, –2, and +4
d.
+4, –4, and +6
Step-by-Step AI Explanation
Verified Method
In KO₂ (superoxide), K is +1. In H₂O₂, O is –1. In H₂SO₄, S is +6.
Q56mcq
If the half-life (t₁/₂) for a first order reaction is 1 minute, then the time required for 99.9% completion of the reaction is closest to:
a.
2 minutes
b.
4 minutes
c.
5 minutes
d.
10 minutes
Correct Answer
Step-by-Step AI Explanation
Verified Method
For a first order reaction, t = (2.303 / k) * log(100 / (100-99.9)) = (2.303 / k) * log(1000). Since k = 0.693 / t₁/₂ = 0.693, t = 2.303 * 3 / 0.693 ≈ 10 minutes.
Q57mcq
The correct order of the wavelength of light absorbed by the following complexes is: A. [Co(NH₃)₆]³⁺ B. [Co(CN)₆]³⁻ C. [Cu(H₂O)₄]²⁺ D. [Ti(H₂O)₆]³⁺
a.
B < D < A < C
b.
B < A < D < C
Correct Answer
c.
C < D < A < B
d.
C < A < D < B
Step-by-Step AI Explanation
Verified Method
Wavelength absorbed is inversely proportional to crystal field splitting (Δ). Stronger ligands cause higher splitting, hence lower wavelength absorbed. Order of field strength: CN⁻ > NH₃ > H₂O.
Q58mcq
Which one of the following compounds can exist as cis-trans isomers?
a.
Pent-1-ene
b.
2-Methylhex-2-ene
c.
1,1-Dimethylcyclopropane
d.
1,2-Dimethylcyclohexane
Correct Answer
Step-by-Step AI Explanation
Verified Method
1,2-Dimethylcyclohexane exists as cis and trans isomers due to the rigidity of the ring system with substituents on different carbons.
Q59mcq
Phosphoric acid ionizes in three steps with their ionization constant values Ka1, Ka2 and Ka3, respectively, while K is the overall ionization constant. Which of the following statements are true? A. log K = log Ka1 + log Ka2 + log Ka3 B. H₃PO₄ is stronger acid than H₂PO₄⁻ and HPO₄²⁻ C. Ka1 > Ka2 > Ka3 D. Ka1 * Ka2 / Ka3 = K
a.
A and B only
b.
A and C only
c.
B, C and D only
d.
A, B and C only
Correct Answer
Step-by-Step AI Explanation
Verified Method
The overall K = Ka1 * Ka2 * Ka3. Log K = log Ka1 + log Ka2 + log Ka3 (True). H₃PO₄ is indeed a stronger acid than its conjugate bases (True). Ka1 > Ka2 > Ka3 is always true for polyprotic acids (True).
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If the molar conductivity (Λm) of a 0.050 mol L⁻¹ solution of a monobasic weak acid is 90 S cm² mol⁻¹, its extent (degree) of dissociation will be [Assume Λ⁰₊ = 349.6 S cm² mol⁻¹ and Λ⁰₋ = 50.4 S cm² mol⁻¹]
a.
0.115
b.
0.125
c.
0.225
d.
0.215
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If the molar conductivity (Λm) of a 0.050 mol L⁻¹ solution of a monobasic weak acid is 90 S cm² mol⁻¹, its extent (degree) of dissociation will be [Assume Λ°+ = 349.6 S cm² mol⁻¹ and Λ°– = 50.4 S cm² mol⁻¹]
a.
0.115
b.
0.125
c.
0.225
d.
0.215
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Given below are two statements: Statement I: A hypothetical diatomic molecule with bond order zero is quite stable. Statement II: As bond order increases, the bond length increases. In the light of the above statements, choose the most appropriate answer from the options given below:
a.
Both statement I and Statement II are true
b.
Both statement I and Statement II are false
c.
Statement I is true but Statement II is false
d.
Statement I is true but Statement II is true
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Given below are two statements: Statement I: A hypothetical diatomic molecule with bond order zero is quite stable. Statement II: As bond order increases, the bond length increases.
a.
Both statement I and Statement II are true
b.
Both statement I and Statement II are false
c.
Statement I is true but Statement II is false
d.
Statement I is true but Statement II is true
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Match the List-I (Example) with List-II (Type of Solution). List-I: (A) Humidity, (B) Alloys, (C) Amalgams, (D) Smoke. List-II: (I) Solid in solid, (II) Liquid in gas, (III) Solid in gas, (IV) Liquid in solid.
a.
A-II, B-IV, C-I, D-III
b.
A-II, B-I, C-IV, D-III
c.
A-III, B-I, C-IV, D-II
d.
A-III, B-II, C-I, D-IV
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Among the following, choose the ones with equal number of atoms. A. 212 g of Na₂CO₃, B. 248 g of Na₂O, C. 240 g of NaOH, D. 12 g of H₂, E. 220 g of CO₂
a.
A, B, and C only
b.
A, B, and D only
c.
B, C, and D only
d.
B, D, and E only
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Given below are two statements: Statement I: Ferromagnetism is considered as an extreme form of paramagnetism. Statement II: The number of unpaired electrons in a Cr²⁺ ion (Z=24) is the same as that of a Nd³⁺ ion (Z=60).
a.
Both Statement I and Statement II are true
b.
Both Statement I and Statement II are false
c.
Statement I is true but Statement II is false
d.
Statement I is false but Statement II is true
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Match the List-I with List-II.
List-I (Mixture): A. CHCl3 + C6H5NH2, B. Crude oil in petroleum industry, C. Glycerol from spent-lye, D. Aniline-water
List-II (Method of Separation): I. Distillation under reduced pressure, II. Steam distillation, III. Fractional distillation, IV. Simple distillation
a.
A-IV, B-III, C-I, D-II
b.
A-IV, B-III, C-II, D-I
c.
A-III, B-IV, C-I, D-II
d.
A-III, B-IV, C-II, D-I
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Match the List-I (Mixture) with List-II (Method of Separation). List-I: (A) CHCl₃ + C₆H₅NH₂, (B) Crude oil, (C) Glycerol from spent-lye, (D) Aniline-water.
a.
A-IV, B-III, C-I, D-II
b.
A-IV, B-III, C-II, D-I
c.
A-III, B-IV, C-I, D-II
d.
A-III, B-IV, C-II, D-I
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For the reaction A(g) ⇌ 2B(g), the backward reaction rate constant is higher than the forward reaction rate constant by a factor of 2500, at 1000 K. [Given: R = 0.0831 L atm mol⁻¹ K⁻¹]. KP for the reaction at 1000 K is
a.
83.1
b.
2.077×10^5
c.
0.033
d.
0.021
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Given below are two statements:
Statement I: Benzenediazonium salt is prepared by the reaction of aniline with nitrous acid at 273-278 K. It decomposes easily in the dry state.
Statement II: Insertion of iodine into the benzene ring is difficult and hence iodobenzene is prepared through the reaction of benzenediazonium salt with KI.
a.
Both Statement I and Statement II are correct
b.
Both Statement I and Statement II are incorrect
c.
Statement I is correct but Statement II is incorrect
d.
Statement I is incorrect but Statement II is correct
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Match List-I with List-II.
List-I: A. Haber process, B. Wacker oxidation, C. Wilkinson catalyst, D. Ziegler catalyst
List-II: I. Fe catalyst, II. PdCl2, III. [(PPh3)3RhCl], IV. TiCl4 with Al(CH3)3
a.
A-I, B-II, C-IV, D-III
b.
A-II, B-III, C-I, D-IV
c.
A-I, B-II, C-III, D-IV
d.
A-I, B-IV, C-III, D-II
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5 moles of liquid X and 10 moles of liquid Y make a solution having a vapour pressure of 70 torr. The vapour pressures of pure X and Y are 63 torr and 78 torr respectively. Which of the following is true regarding the described solution?
a.
The solution shows positive deviation.
b.
The solution shows negative deviation.
c.
The solution is ideal.
d.
The solution has volume greater than the sum of individual volumes.
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Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R):
Assertion (A): RI undergoes SN2 reaction faster than RCl.
Reason (R): Iodine is a better leaving group because of its large size.
In the light of the above statements, choose the correct answer from the options given below:
a.
Both A and R are true and R is the correct explanation of A.
b.
Both A and R are true but R is not the correct explanation of A.
c.
A is true but R is false.
d.
A is false but R is true.
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Given below are two statements: Assertion (A): R-I undergoes SN2 reaction faster than R-Cl. Reason (R): Iodine is a better leaving group because of its large size.
a.
Both A and R are true and R is the correct explanation of A.
b.
Both A and R are true but R is not the correct explanation of A.
c.
A is true but R is false.
d.
A is false but R is true.
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The standard heat of formation, in kcal/mol of Ba2+ is: [Given: standard heat of formation of SO4 2- ion (aq)= –216 kcal/mol, standard heat of crystallization of BaSO4(s) = –4.5 kcal/mol, standard heat of formation of BaSO4(s) = –349 kcal/mol]
a.
-128.5
b.
-133.0
c.
+133.0
d.
+220.5
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The standard heat of formation, in kcal/mol of Ba2+(aq) is: [Given: standard heat of formation of SO4 2-(aq) = –216 kcal/mol, standard heat of crystallization of BaSO4(s) = –4.5 kcal/mol, standard heat of formation of BaSO4(s) = –349 kcal/mol]
a.
–128.5
b.
–133.0
c.
+133.0
d.
+220.5
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Identify the correct orders against the property mentioned:
A. H2O > NH3 > CHCl3 - dipole moment
B. XeF4 > XeO3 > XeF2 – number of lone pairs on central atom
C. O–H > C –H > N–O – bond length
D. N2 > O2 > H2 – bond enthalpy
Choose the correct answer from the options given below:
a.
A, D only
b.
B, D only
c.
A, C only
d.
B, C only
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Higher yield of NO in N2(g) + O2(g) ⇌ 2NO(g) can be obtained at [ΔH of the reaction = + 180.7 kJ mol–1]
A. higher temperature
B. lower temperature
C. higher concentration of N2
D. higher concentration of O2
Choose the correct answer from the options given below:
a.
A, D only
b.
B, C only
c.
B, C, D only
d.
A, C, D only
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If the rate constant of a reaction is 0.03 s–1, how much time does it take for 7.2 mol L–1 concentration of the reactant to get reduced to 0.9 mol L–1? (Given: log 2 = 0.301)
a.
69.3 s
b.
23.1 s
c.
210 s
d.
21.0 s
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Match List I with List II.
List I List II
A. Adenosine I. Nitrogen base
B. Adenylic acid II. Nucleotide
C. Adenine III. Nucleoside
D. Alanine IV. Amino acid
a.
A-III, B-IV, C-II, D-I
b.
A-III, B-II, C-IV, D-I
c.
A-III, B-II, C-I, D-IV
d.
A-II, B-III, C-I, D-IV
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Match List I with List II.
List I (Molecule) | List II (Category)
A. Adenosine | I. Nitrogen base
B. Adenylic acid | II. Nucleotide
C. Adenine | III. Nucleoside
D. Alanine | IV. Amino acid
Choose the option with all correct matches.
a.
A-III, B-IV, C-II, D-I
b.
A-III, B-II, C-IV, D-I
c.
A-III, B-II, C-I, D-IV
d.
A-II, B-III, C-I, D-IV
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