The following solutions were prepared by dissolving 10 g of glucose (C6H12O6) in 250 ml of water (P1), 10 g of urea (CH4N2O) in 250 ml of water (P2) and 10 g of sucrose (C12H22O11) in 250 ml of water (P3). The right option for the decreasing order of osmotic pressure of these solutions is :
a.
P1 > P2 > P3
b.
P2 > P3 > P1
c.
P3 > P1 > P2
d.
P2 > P1 > P3
Correct Answer
Step-by-Step AI Explanation
Verified Method
Osmotic pressure Pi = iCRT. Since i=1 for all, Pi is proportional to concentration C = n/V. Molar masses: Urea = 60, Glucose = 180, Sucrose = 342. Moles: n(Urea) = 10/60 = 0.166, n(Glucose) = 10/180 = 0.055, n(Sucrose) = 10/342 = 0.029. Thus, order is P2 > P1 > P3.
Q53mcq
Tritium, a radioactive isotope of hydrogen, emits which of the following particles ?
a.
Alpha (α)
b.
Gamma (γ)
c.
Neutron (n)
d.
Beta (β-)
Correct Answer
Step-by-Step AI Explanation
Verified Method
Tritium (3H) is radioactive and decays by emitting a beta particle (beta- decay) to form Helium-3.
Q54mcq
Which one of the following methods can be used to obtain highly pure metal which is liquid at room temperature?
a.
Chromatography
b.
Distillation
Correct Answer
c.
Zone refining
d.
Electrolysis
Step-by-Step AI Explanation
Verified Method
Distillation is very useful for low boiling metals like mercury (liquid at room temperature).
Q55mcq
BF3 is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are :
a.
sp3 and 6
b.
sp2 and 6
Correct Answer
c.
sp2 and 8
d.
sp3 and 4
Step-by-Step AI Explanation
Verified Method
Boron in BF3 has 3 bond pairs around it, no lone pairs, so it is sp2 hybridized. It has 6 electrons in its valence shell, making it electron deficient.
Q55mcq
BF3 is planar and electron deficient compound. Hybridization and number of electrons around the central atom, respectively are :
a.
sp3 and 6
b.
sp2 and 6
Correct Answer
c.
sp2 and 8
d.
sp3 and 4
Step-by-Step AI Explanation
Verified Method
Boron has 3 valence electrons, forming 3 bonds with fluorine, resulting in sp2 hybridization and 6 electrons in its valence shell.
Q57mcq
Noble gases are named because of their inertness towards reactivity. Identify an incorrect statement about them.
a.
Noble gases have very high melting and boiling points.
Correct Answer
b.
Noble gases have weak dispersion forces.
c.
Noble gases have large positive values of electron gain enthalpy.
d.
Noble gases are sparingly soluble in water.
Step-by-Step AI Explanation
Verified Method
Noble gases have very low melting and boiling points due to the presence of weak London dispersion forces.
Q57mcq
Noble gases are named because of their inertness towards reactivity. Identify an incorrect statement about them.
a.
Noble gases have very high melting and boiling points.
Correct Answer
b.
Noble gases have weak dispersion forces.
c.
Noble gases have large positive values of electron gain enthalpy.
d.
Noble gases are sparingly soluble in water.
Step-by-Step AI Explanation
Verified Method
Noble gases have very low melting and boiling points due to weak interatomic dispersion forces, not high ones.
Q58mcq
Ethylene diaminetetraacetate (EDTA) ion is :
a.
Unidentate ligand
b.
Bidentate ligand with two “N” donor atoms
c.
Tridentate ligand with three “N” donor atoms
d.
Hexadentate ligand with four “O” and two “N” donor atoms
Correct Answer
Step-by-Step AI Explanation
Verified Method
EDTA(4-) is a hexadentate ligand as it has six donor atoms: four oxygen atoms (from carboxylate groups) and two nitrogen atoms.
Q58mcq
Ethylene diaminetetraacetate (EDTA) ion is :
a.
Unidentate ligand
b.
Bidentate ligand with two “N” donor atoms
c.
Tridentate ligand with three “N” donor atoms
d.
Hexadentate ligand with four “O” and two “N” donor atoms
Correct Answer
Step-by-Step AI Explanation
Verified Method
EDTA is a hexadentate ligand with 4 oxygen donor atoms (from carboxylate groups) and 2 nitrogen donor atoms (from amine groups).
Q61mcq
Which of the following reactions is the metal displacement reaction ? Choose the right option.
a.
Cr2O3 + 2Al -> Al2O3 + 2Cr
Correct Answer
b.
Fe + 2HCl -> FeCl2 + H2
c.
2Pb(NO3)2 -> 2PbO + 4NO2 + O2
d.
2KClO3 -> 2KCl + 3O2
Step-by-Step AI Explanation
Verified Method
Metal displacement involves one metal displacing another from its compound; Al displaces Cr from Cr2O3.
🎉 10 Free Sample Solutions Completed
Unlock All 41 Questions & Solutions
Sign up free in seconds to unlock step-by-step AI answers for the remaining 31 questions.
Statement I : Acid strength increases in the order given as HF << HCl << HBr << HI. Statement II : As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases. In the light of the above statements, choose the correct answer from the options given below.
a.
Both Statement I and Statement II are false.
b.
Statement I is correct but Statement II is false.
c.
Statement I is incorrect but Statement II is true.
d.
Both Statement I and Statement II are true.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Statement I: Acid strength increases in the order given as HF << HCl << HBr << HI. Statement II: As the size of the elements F, Cl, Br, I increases down the group, the bond strength of HF, HCl, HBr and HI decreases and so the acid strength increases. In the light of the above statements, choose the correct answer from the options given below.
a.
Both Statement I and Statement II are false.
b.
Statement I is correct but Statement II is false.
c.
Statement I is incorrect but Statement II is true.
d.
Both Statement I and Statement II are true.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Match List - I with List - II. List - I (a) PCl5 (b) SF6 (c) BrF5 (d) BF3 List - II (i) Square pyramidal (ii) Trigonal planar (iii) Octahedral (iv) Trigonal bipyramidal
a.
(a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
b.
(a)-(iii), (b)-(i), (c)-(iv), (d)-(ii)
c.
(a)-(iv), (b)-(iii), (c)-(ii), (d)-(i)
d.
(a)-(iv), (b)-(iii), (c)-(i), (d)-(ii)
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The molar conductance of NaCl, HCl and CH3COONa at infinite dilution are 126.45, 426.16 and 91.0 S cm2 mol−1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer.
a.
390.71 S cm2 mol−1
b.
698.28 S cm2 mol−1
c.
540.48 S cm2 mol−1
d.
201.28 S cm2 mol−1
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The pKb of dimethylamine and pKa of acetic acid are 3.27 and 4.77 respectively at T (K). The correct option for the pH of dimethylammonium acetate solution is :
a.
5.50
b.
7.75
c.
6.25
d.
8.50
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
An organic compound contains 78% (by wt.) carbon and remaining percentage of hydrogen. The right option for the empirical formula of this compound is : [Atomic wt. of C is 12, H is 1]
a.
CH2
b.
CH3
c.
CH4
d.
CH
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The slope of Arrhenius Plot ln k v/s 1/T of first order reaction is -5×10^3 K. The value of Ea of the reaction is. Choose the correct option for your answer. [Given R=8.314 JK^-1 mol^-1]
a.
83.0 kJ mol^-1
b.
166 kJ mol^-1
c.
-83 kJ mol^-1
d.
41.5 kJ mol^-1
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The molar conductivity of 0.007 M acetic acid is 20 S cm^2 mol^-1. What is the dissociation constant of acetic acid? [Given: Lambda_H+ = 350 S cm^2 mol^-1, Lambda_CH3COO- = 50 S cm^2 mol^-1]
a.
2.50x10^-4 mol L^-1
b.
1.75x10^-5 mol L^-1
c.
2.50x10^-5 mol L^-1
d.
1.75x10^-4 mol L^-1
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The correct option for the value of vapour pressure of a solution at 45°C with benzene to octane in molar ratio 3 : 2 is: [At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]
a.
168 mm of Hg
b.
336 mm of Hg
c.
350 mm of Hg
d.
160 mm of Hg
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
