For the reaction, 2Cl(g) → Cl2(g), the correct option is:
a.
ΔrH < 0 and ΔrS < 0
Correct Answer
b.
ΔrH > 0 and ΔrS > 0
c.
ΔrH > 0 and ΔrS < 0
d.
ΔrH < 0 and ΔrS > 0
Step-by-Step AI Explanation
Verified Method
Formation of Cl2 from atomic chlorine releases energy, so the reaction is exothermic and ΔrH < 0. Two gaseous species form one gaseous molecule, so disorder decreases and ΔrS < 0.
Q2mcq
Which of the following set of molecules will have zero dipole moment?
BF3 is trigonal planar and symmetric, BeF2 is linear and symmetric, and CO2 is linear and symmetric. 1,4-dichlorobenzene has symmetrical substitution, so its dipoles cancel. The other options include polar molecules or unsymmetrical isomers.
Q3mcq
The correct option for free expansion of an ideal gas under adiabatic condition is:
a.
q > 0, ΔT > 0 and w > 0
b.
q = 0, ΔT = 0 and w = 0
Correct Answer
c.
q = 0, ΔT < 0 and w > 0
d.
q < 0, ΔT = 0 and w = 0
Step-by-Step AI Explanation
Verified Method
In free expansion against vacuum, no work is done (w = 0). Under adiabatic conditions, q = 0. For an ideal gas, internal energy depends only on temperature, so ΔT = 0.
Q4mcq
Identify a molecule which does not exist.
a.
O2
b.
He2
Correct Answer
c.
Li2
d.
C2
Step-by-Step AI Explanation
Verified Method
He2 does not exist as a stable molecule because helium atoms have a completely filled 1s shell and bonding is not favored. O2 and Li2 are known stable species; C2 exists as a diatomic molecule under suitable conditions.
Q5mcq
Match the following and identify the correct option.
(a) CO + H2
(b) Temporary hardness of water
(c) B2H6
(d) H2O2
CO + H2 is synthesis gas; temporary hardness of water is due to bicarbonates of Ca and Mg; B2H6 is an electron-deficient hydride; H2O2 has a non-planar (skewed) structure.
Q6mcq
Identify the correct statement from the following:
a.
Pig iron can be moulded into a variety of shapes.
b.
Wrought iron is impure iron with 4% carbon.
c.
Blister copper has blistered appearance due to evolution of CO2.
d.
Vapour phase refining is carried out for nickel by Van Arkel method.
Correct Answer
Step-by-Step AI Explanation
Verified Method
Van Arkel method is a vapour phase refining process used for metals like titanium, zirconium and nickel. The other statements are incorrect: pig iron is brittle and not easily moulded; wrought iron has very low carbon content; blister copper gets its blistered appearance due to evolution of SO2, not CO2.
Q6mcq
Identify the correct statement from the following:
a.
Pig iron can be moulded into a variety of shapes.
b.
Wrought iron is impure iron with 4% carbon.
c.
Blister copper has blistered appearance due to evolution of CO2.
d.
Vapour phase refining is carried out for Nickel by Van Arkel method.
Correct Answer
Step-by-Step AI Explanation
Verified Method
Van Arkel method is used for vapour phase refining of metals such as Ti, Zr and Ni. Pig iron is brittle, wrought iron has very low carbon content, and blister copper gets its appearance due to escaping SO2, not CO2.
Q7mcq
The freezing point depression constant (Kf) of benzene is 5.12 K kg mol−1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off upto two decimal places):
a.
0.60 K
b.
0.20 K
Correct Answer
c.
0.80 K
d.
0.40 K
Step-by-Step AI Explanation
Verified Method
ΔTf = Kf m = 5.12 × 0.078 = 0.39936 K ≈ 0.40 K. Among the provided options, 0.40 K is the correct value.
Q7mcq
The freezing point depression constant (Kf) of benzene is 5.12 K kg mol−1. The freezing point depression for the solution of molality 0.078 m containing a non-electrolyte solute in benzene is (rounded off up to two decimal places):
a.
0.60 K
b.
0.20 K
c.
0.80 K
d.
0.40 K
Correct Answer
Step-by-Step AI Explanation
Verified Method
ΔTf = Kf × m = 5.12 × 0.078 = 0.39936 K ≈ 0.40 K.
Q8mcq
Match the following:
Oxide — Nature
(a) CO
(b) BaO
(c) Al2O3
(d) Cl2O7
Which of the following is the correct option?
a.
(iv)(iii)(ii)(i)
b.
(i)(ii)(iii)(iv)
Correct Answer
c.
(ii)(i)(iv)(iii)
d.
(iii)(iv)(i)(ii)
Step-by-Step AI Explanation
Verified Method
CO is neutral, BaO is basic, Al2O3 is amphoteric, and Cl2O7 is acidic. So the matching is (a) ii, (b) i, (c) iv, (d) iii.
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Hydrolysis of sucrose is given by the following reaction:
Sucrose + H2O ⇌ Glucose + Fructose
If the equilibrium constant (Kc) is 2 × 10^13 at 300 K, the value of ΔrG° at the same temperature will be:
a.
−8.314 J mol−1 K−1 × 300 K × ln(4 × 10^13)
b.
−8.314 J mol−1 K−1 × 300 K × ln(2 × 10^13)
c.
8.314 J mol−1 K−1 × 300 K × ln(2 × 10^13)
d.
8.314 J mol−1 K−1 × 300 K × ln(3 × 10^13)
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Urea reacts with water to form A which will decompose to form B. B when passed through Cu2+ (aq), deep blue colour solution C is formed. What is the formula of C from the following?
a.
CuCO3·Cu(OH)2
b.
CuSO4
c.
[Cu(NH3)4]2+
d.
Cu(OH)2
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Identify the correct statements from the following:
(a) CO2(g) is used as refrigerant for ice-cream and frozen food.
(b) The structure of C60 contains twelve six-membered rings and twenty-five carbon rings.
(c) ZSM-5, a type of zeolite, is used to convert alcohols into gasoline.
(d) CO is colorless and odourless gas.
a.
(c) and (d) only
b.
(a), (b) and (c) only
c.
(a) and (c) only
d.
(b) and (c) only
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The oxidation states of chromium in CrO4^2− and Cr2O7^2− are not the same.
b.
Cr2+ (d4) is a stronger reducing agent than Fe2+ (d6) in water.
c.
The transition metals and their compounds are known for their catalytic activity due to their ability to adopt multiple oxidation states and to form complexes.
d.
Interstitial compounds are those that are formed when small atoms like H, C or N are trapped inside the crystal lattices of metals.
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Match the following columns and select the correct option.
Column I Column II
(a) Clostridium butylicum (i) Cyclosporin-A
(b) Trichoderma polysporum (ii) Butyric Acid
(c) Monascus purpureus (iii) Citric Acid
(d) Aspergillus niger (iv) Blood cholesterol lowering agent
a.
(a)(b)(c)(d) = (iv)(iii)(ii)(i)
b.
(a)(b)(c)(d) = (iii)(iv)(ii)(i)
c.
(a)(b)(c)(d) = (ii)(i)(iv)(iii)
d.
(a)(b)(c)(d) = (i)(ii)(iv)(iii)
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Match the following:
(a) Inhibitor of catalytic activity
(b) Possess peptide bonds
(c) Cell wall material in fungi
(d) Secondary metabolite
Choose the correct option from the following:
Column I Column II
(i) Ricin
(ii) Malonate
(iii) Chitin
(iv) Collagen
a.
(a)(b)(c)(d) = (ii)(iii)(i)(iv)
b.
(a)(b)(c)(d) = (ii)(iv)(iii)(i)
c.
(a)(b)(c)(d) = (iii)(i)(iv)(ii)
d.
(a)(b)(c)(d) = (iii)(iv)(i)(ii)
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