According to Molecular Orbital Theory, the bond order of He2 is zero (1/2(2-2) = 0), so it does not exist.
Q2mcq
Sucrose on hydrolysis gives:
a.
alpha-D-Glucose + beta-D-Glucose
b.
alpha-D-Glucose + beta-D-Fructose
Correct Answer
c.
alpha-D-Fructose + beta-D-Fructose
d.
beta-D-Glucose + alpha-D-Fructose
Step-by-Step AI Explanation
Verified Method
Sucrose is a disaccharide that on hydrolysis yields one molecule of alpha-D-glucose and one molecule of beta-D-fructose.
Q3mcq
Which one of the following is the most abundant protein in the animals?
a.
Collagen
Correct Answer
b.
Lectin
c.
Insulin
d.
Haemoglobin
Step-by-Step AI Explanation
Verified Method
Collagen is the most abundant protein in the animal kingdom.
Q4mcq
A tertiary butyl carbocation is more stable than a secondary butyl carbocation because of which of the following?
a.
+R effect of -CH3 groups
b.
-R effect of -CH3 groups
c.
Hyperconjugation
Correct Answer
d.
-I effect of -CH3 groups
Step-by-Step AI Explanation
Verified Method
Carbocation stability increases with more alkyl groups due to inductive effect and hyperconjugation. Hyperconjugation with adjacent C-H bonds provides additional stability.
Q5mcq
Calculated spin-only magnetic moment of Cr2+ ion is:
a.
4.90 BM
Correct Answer
b.
5.92 BM
c.
2.84 BM
d.
3.87 BM
Step-by-Step AI Explanation
Verified Method
Cr2+ has a d4 configuration. The number of unpaired electrons (n) = 4. Magnetic moment = sqrt(n(n+2)) = sqrt(4(6)) = sqrt(24) ≈ 4.90 BM.
Q6mcq
The calculated spin only magnetic moment of Cr 2+ ion is:
a.
4.90 BM
Correct Answer
b.
5.92 BM
c.
2.84 BM
d.
3.87 BM
Step-by-Step AI Explanation
Verified Method
Cr atom is [Ar] 3d5 4s1. Cr 2+ is [Ar] 3d4. It has 4 unpaired electrons. Magnetic moment = sqrt(n(n+2)) = sqrt(4(6)) = sqrt(24) ≈ 4.90 BM.
Q7mcq
What is the change in oxidation number of carbon in the following reaction? CH4(g) + 4Cl2(g) -> CCl4(l) + 4HCl(g)
a.
0 to +4
b.
-4 to +4
Correct Answer
c.
0 to -4
d.
+4 to +4
Step-by-Step AI Explanation
Verified Method
In CH4, C is in -4 oxidation state. In CCl4, C is in +4 oxidation state.
Q8mcq
Find out the solubility of Ni(OH)2 in 0.1M NaOH. Given that the ionic product of Ni(OH)2 is 2x10^-15.
The mixture which shows positive deviation from Raoult’s law is:
a.
Benzene + Toluene
b.
Acetone + Chloroform
c.
Chloroethane + Bromoethane
d.
Ethanol + Acetone
Correct Answer
Step-by-Step AI Explanation
Verified Method
Ethanol + Acetone is an example of a solution showing positive deviation from Raoult's law as the hydrogen bonds between ethanol molecules are weakened by the addition of acetone.
Q10mcq
The mixture which shows positive deviation from Raoult’s law is:
a.
Benzene + Toluene
b.
Acetone + Chloroform
c.
Chloroethane + Bromoethane
d.
Ethanol + Acetone
Correct Answer
Step-by-Step AI Explanation
Verified Method
Ethanol + Acetone shows positive deviation because the interaction between the components is weaker than the pure component interactions, leading to increased vapor pressure.
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A mixture of N2 and Ar gases in a cylinder contains 7 g of N2 and 8 g of Ar. If the total pressure of the mixture of the gases in the cylinder is 27 bar, the partial pressure of N2 is: [Use atomic masses: N=14, Ar=40]
a.
12 bar
b.
15 bar
c.
18 bar
d.
9 bar
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