When 2 moles of gas particles combine to form 1 mole, the number of particles decreases, leading to a decrease in randomness and a negative change in entropy.
Q137mcq
For the chemical reaction N2(g) + 3H2(g) → 2NH3(g)
a.
-d[N2]/dt = 1/2 d[NH3]/dt
Correct Answer
b.
2/3 d[H2]/dt = 3/2 d[NH3]/dt
c.
-1/3 d[H2]/dt = -1/2 d[NH3]/dt
d.
-d[N2]/dt = 3/2 d[NH3]/dt
Step-by-Step AI Explanation
Verified Method
The rate of reaction is given by -d[N2]/dt = -(1/3)d[H2]/dt = (1/2)d[NH3]/dt. Therefore, -d[N2]/dt = 1/2 d[NH3]/dt.
Q138mcq
Which of the following diatomic molecular species has only π bonds according to Molecular Orbital Theory?
a.
C2
Correct Answer
b.
Be2
c.
O2
d.
N2
Step-by-Step AI Explanation
Verified Method
In the C2 molecule, the configuration is σ1s^2 σ*1s^2 σ2s^2 σ*2s^2 π2p_x^2 π2p_y^2. Both bonds are π bonds.
Q139mcq
Which of the following is an incorrect statement?
a.
GeX4(X = F, Cl, Br, I) is more stable than GeX2
b.
SnF4 is ionic in nature
c.
PbF4 is covalent in nature
Correct Answer
d.
SiCl4 is easily hydrolysed
Step-by-Step AI Explanation
Verified Method
PbF4 is an ionic compound, not covalent, because the ionic character increases down the group for fluorides.
Q139mcq
Which of the following is incorrect statement?
a.
GeX4(X = F, Cl, Br, I) is more stable than GeX2
b.
SnF4 is ionic in nature
c.
PbF4 is covalent in nature
Correct Answer
d.
SiCl4 is easily hydrolysed
Step-by-Step AI Explanation
Verified Method
PbF4 is an ionic compound, so the statement that it is covalent in nature is incorrect.
Q140mcq
Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
a.
25 J
b.
30 J
Correct Answer
c.
-30 J
d.
5 kJ
Step-by-Step AI Explanation
Verified Method
Work done by the gas = P_ext * ΔV = 2 bar * (0.25 - 0.1) L = 2 * 0.15 L bar = 0.3 L bar. Converting to Joules (1 L bar = 100 J), work = 0.3 * 100 = 30 J.
Q140mcq
Under isothermal condition, a gas at 300 K expands from 0.1 L to 0.25 L against a constant external pressure of 2 bar. The work done by the gas is [Given that 1 L bar = 100 J]
a.
25 J
b.
30 J
Correct Answer
c.
-30 J
d.
5 kJ
Step-by-Step AI Explanation
Verified Method
Work done by the gas is W = -Pext * ΔV. Given Pext = 2 bar, ΔV = 0.25 - 0.1 = 0.15 L. Work done by the gas = +Pext * ΔV = 2 * 0.15 = 0.3 L bar = 30 J.
Q141mcq
The compound that is most difficult to protonate is :
a.
Dimethyl ether (CH3-O-CH3)
b.
Phenol (Ph-OH)
Correct Answer
c.
Water (H-O-H)
d.
Methanol (H3C-O-H)
Step-by-Step AI Explanation
Verified Method
In phenol, the lone pair on the oxygen atom is involved in resonance with the benzene ring, making it less available for protonation compared to alcohols and ethers.
Q142mcq
Which of the following is an amphoteric hydroxide?
a.
Mg(OH)2
b.
Be(OH)2
Correct Answer
c.
Sr(OH)2
d.
Ca(OH)2
Step-by-Step AI Explanation
Verified Method
Be(OH)2 is amphoteric in nature, while other group 2 hydroxides are basic.
Q144mcq
The biodegradable polymer is -
a.
nylon-6
b.
Buna-S
c.
nylon-6, 6
d.
nylon 2-nylon 6
Correct Answer
Step-by-Step AI Explanation
Verified Method
Nylon-2-nylon-6 is a biodegradable polyamide copolymer.
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Match the following: (a) Pure nitrogen (i) Chlorine (b) Haber process (ii) Sulphuric acid (c) Contact process (iii) Ammonia (d) Deacon’s process (iv) Sodium azide or Barium azide. Which of the following is the correct option?
a.
(1) (iii) (iv) (ii) (i)
b.
(2) (iv) (iii) (ii) (i)
c.
(3) (i) (ii) (iii) (iv)
d.
(4) (ii) (iv) (i) (iii)
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For a cell involving one electron E°cell = 0.59 V at 298 K, the equilibrium constant for the cell reaction is : [Given that (RT/F) * 2.303 = 0.059 V at T = 298 K]
a.
1.0 × 10^10
b.
1.0 × 10^30
c.
1.0 × 10^2
d.
1.0 × 10^5
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For the cell reaction 2Fe3+(aq) + 2I-(aq) -> 2Fe2+(aq) + I2(aq), E°cell = 0.24 V at 298 K. The standard Gibbs energy (ΔrG°) of the cell reaction is: [Given that Faraday constant F = 96500 C mol-1]
a.
46.32 kJ mol-1
b.
23.16 kJ mol-1
c.
-46.32 kJ mol-1
d.
-23.16 kJ mol-1
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For the cell reaction 2Fe3+(aq) + 2I–(aq) → 2Fe2+(aq) + I2(aq) E°cell = 0.24 V at 298 K. The standard Gibbs energy (ΔrG°) of the cell reaction is : [Given that Faraday constant F = 96500 C mol–1]
a.
46.32 kJ mol–1
b.
23.16 kJ mol–1
c.
–46.32 kJ mol–1
d.
–23.16 kJ mol–1
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An alkene “A” on reaction with O3 and Zn + H2O gives propanone and ethanal in equimolar ratio. Addition of HCl to alkene “A” gives “B” as the major product. The structure of product “B” is:
a.
H3C – C(Cl)(CH3) – CH2 – CH3
b.
H3C – CH(Cl) – CH(CH3)2
c.
Cl – CH2 – CH2 – CH(CH3)2
d.
H3C – CH2 – CH(CH2Cl) – CH3
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Match the Xenon compounds in Column-I with its structure in column-II and assign the correct code: (a) XeF4 (i) pyramidal (b) XeF6 (ii) square planar (c) XeOF4 (iii) distorted octahedral (d) XeO3 (iv) square pyramidal
a.
(1) (a)-(ii), (b)-(iii), (c)-(i), (d)-(iv)
b.
(2) (a)-(iii), (b)-(iv), (c)-(i), (d)-(ii)
c.
(3) (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
d.
(4) (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
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