The two functional groups characteristic of sugars are
a.
Hydroxyl and methyl
b.
Carbonyl and methyl
c.
Carbonyl and hydroxyl
Correct Answer
d.
Carbonyl and phosphate
Step-by-Step AI Explanation
Verified Method
Carbohydrates (sugars) are defined as polyhydroxy aldehydes or polyhydroxy ketones; thus, they possess carbonyl and hydroxyl groups.
Q136mcq
The correct order of N-compounds in its decreasing order of oxidation states is
a.
HNO3, NO, N2, NH4Cl
Correct Answer
b.
HNO3, NO, NH4Cl, N2
c.
NH4Cl, N2, NO, HNO3
d.
HNO3, NH4Cl, NO, N2
Step-by-Step AI Explanation
Verified Method
The oxidation states are: HNO3 (+5), NO (+2), N2 (0), NH4Cl (-3). The order is +5 > +2 > 0 > -3.
Q137mcq
The correct order of atomic radii in group 13 elements is
a.
B < Al < In < Ga < Tl
b.
B < Al < Ga < In < Tl
c.
B < Ga < Al < In < Tl
Correct Answer
d.
B < Ga < Al < Tl < In
Step-by-Step AI Explanation
Verified Method
Due to poor shielding of d and f electrons (lanthanoid contraction), the atomic radii of Ga is smaller than Al and Tl is slightly larger than In, resulting in the order B < Ga < Al < In < Tl.
Q137mcq
The correct order of atomic radii in group 13 elements is
a.
B < Al < In < Ga < Tl
b.
B < Al < Ga < In < Tl
c.
B < Ga < Al < In < Tl
Correct Answer
d.
B < Ga < Al < Tl < In
Step-by-Step AI Explanation
Verified Method
Due to poor shielding by d-electrons in Ga, its atomic radius is slightly smaller than expected, leading to the order: B (85 pm) < Ga (135 pm) < Al (143 pm) < In (167 pm) < Tl (170 pm).
Q138mcq
Considering Ellingham diagram, which of the following metals can be used to reduce alumina?
a.
Fe
b.
Zn
c.
Cu
d.
Mg
Correct Answer
Step-by-Step AI Explanation
Verified Method
A metal more reactive than aluminium can reduce alumina (Al2O3); Mg is more reactive than Al.
Q138mcq
Considering Ellingham diagram, which of the following metals can be used to reduce alumina?
a.
Fe
b.
Zn
c.
Cu
d.
Mg
Correct Answer
Step-by-Step AI Explanation
Verified Method
A metal with a more negative Gibbs free energy of oxide formation than Aluminium can act as a reducing agent for alumina. Magnesium (Mg) is more reactive than Al.
Q139mcq
Which one of the following elements is unable to form MF6^3- ion?
a.
Ga
b.
Al
c.
In
d.
B
Correct Answer
Step-by-Step AI Explanation
Verified Method
Boron (B) lacks vacant d-orbitals in its valence shell, preventing it from extending its covalency beyond 4; thus, it cannot form an ion like BF6^3-.
Q139mcq
Which one of the following elements is unable to form MF6^3– ion?
a.
Ga
b.
Al
c.
In
d.
B
Correct Answer
Step-by-Step AI Explanation
Verified Method
Boron has no vacant d-orbitals in its valence shell, so it cannot extend its covalency beyond 4, and thus cannot form the MF6^3– ion.
Q140mcq
Which of the following statements is not true for halogens?
a.
All form monobasic oxyacids
b.
All are oxidizing agents
c.
Chlorine has the highest electron-gain enthalpy
d.
All but fluorine show positive oxidation states
Correct Answer
Step-by-Step AI Explanation
Verified Method
Due to high electronegativity and small size, fluorine exhibits an oxidation state of +1 in HOF, which is the only oxoacid it forms. Thus, the statement that it does not show positive oxidation states is incorrect.
Q141mcq
In the structure of ClF3, the number of lone pair of electrons on central atom ‘Cl’ is
a.
One
b.
Two
Correct Answer
c.
Three
d.
Four
Step-by-Step AI Explanation
Verified Method
Chlorine (group 17) has 7 valence electrons. In ClF3, it forms 3 covalent bonds with fluorine, leaving (7-3)/2 = 2 lone pairs on the central Cl atom.
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A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
a.
1.4
b.
3.0
c.
4.4
d.
2.8
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Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH ≡ CH
b.
CH2 = CH2
c.
CH4
d.
CH3 – CH3
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Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH ≡ CH
b.
CH2 = CH2
c.
CH4
d.
CH3CH3
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The compound C7H8 undergoes the following reactions: Toluene (C7H8) reacts with 3Cl2/delta to give A, then Br2/Fe to give B, then Zn/HCl to give C. The product 'C' is
a.
m-bromotoluene
b.
o-bromotoluene
c.
p-bromotoluene
d.
3-bromo-2,4,6-trichlorotoluene
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Compound A, C8H10O, is found to react with NaOI (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively
a.
H3CCH2 – OH and I2
b.
CH2 – CH – OH and I2
c.
OH and I2 with CH3
d.
CH – CH3 and I2 with OH
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Compound A, C8H10O, is found to react with NaOI (produced by reacting Y with NaOH) and yields a yellow precipitate with characteristic smell. A and Y are respectively
a.
Phenylethanol and I2
b.
1-Phenylethanol and I2
c.
Benzyl alcohol and I2
d.
1-Phenylethanol and I2 (structure context)
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For the redox reaction MnO4- + C2O4 2- + H+ -> Mn2+ + CO2 + H2O, the correct coefficients of the reactants for the balanced equation are (MnO4-, C2O4 2-, H+):
a.
16, 5, 2
b.
2, 5, 16
c.
5, 16, 2
d.
2, 16, 5
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The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is –200 kJ mol–1. The bond dissociation energy of X2 will be:
a.
200 kJ mol–1
b.
100 kJ mol–1
c.
400 kJ mol–1
d.
800 kJ mol–1
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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is:
a.
Mg2X3
b.
MgX2
c.
Mg3X2
d.
Mg2X
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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s^2 2s^2 2p^3, the simplest formula for this compound is
a.
Mg2X3
b.
MgX2
c.
Mg3X2
d.
Mg2X
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The correct difference between first and second order reactions is that
a.
The rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
b.
The half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
c.
The rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
d.
A first-order reaction can catalyzed; a second-order reaction cannot be catalyzed
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Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below: BrO4- (1.82 V) -> BrO3- (1.5 V) -> HBrO (1.595 V) -> Br2 (1.0652 V) -> Br-. Then the species undergoing disproportionation is
a.
BrO3-
b.
BrO4-
c.
HBrO
d.
Br2
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Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram. Then the species undergoing disproportionation is
a.
BrO3–
b.
BrO4–
c.
HBrO
d.
Br2
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The solubility of BaSO4 in water is 2.42 × 10⁻³ gL⁻¹ at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol⁻¹)
a.
1.08 × 10⁻¹⁰ mol² L⁻²
b.
1.08 × 10⁻¹² mol² L⁻²
c.
1.08 × 10⁻⁸ mol² L⁻²
d.
1.08 × 10⁻¹⁴ mol² L⁻²
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The solubility of BaSO4 in water is 2.42 × 10^–3 gL^–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol^–1)
a.
1.08 × 10^–10 mol^2 L^–2
b.
1.08 × 10^–12 mol^2 L^–2
c.
1.08 × 10^–8 mol^2 L^–2
d.
1.08 × 10^–14 mol^2 L^–2
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Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: a. 60 mL M/10 HCl + 40 mL M/10 NaOH; b. 55 mL M/10 HCl + 45 mL M/10 NaOH; c. 75 mL M/5 HCl + 25 mL M/5 NaOH; d. 100 mL M/10 HCl + 100 mL M/10 NaOH. pH of which one of them will be equal to 1?
a.
b
b.
a
c.
c
d.
d
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Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code:
Column I | Column II
a. Co3+ | i. sqrt(8) BM
b. Cr3+ | ii. sqrt(35) BM
c. Fe3+ | iii. sqrt(3) BM
d. Ni2+ | iv. sqrt(24) BM
| v. sqrt(15) BM
a.
a-iv, b-v, c-ii, d-i
b.
a-i, b-ii, c-iii, d-iv
c.
a-iii, b-v, c-i, d-ii
d.
a-iv, b-i, c-ii, d-iii
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Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II: a. Co3+, b. Cr3+, c. Fe3+, d. Ni2+. Column II: i. √8 BM, ii. √35 BM, iii. √3 BM, iv. √24 BM, v. √15 BM
a.
abcd: (1) iv v ii i
b.
abcd: (2) i ii iii iv
c.
abcd: (3) iii v i ii
d.
abcd: (4) iv i ii iii
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