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NEET 2018 CODE-NN

2018 · 38 questions · First 10 Solutions Free
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Q1 mcq
The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
b.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
c.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
d.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0 Correct Answer
Step-by-Step AI Explanation
Verified Method
For a first-order reaction, t1/2 = ln2/k (independent of concentration). For a second-order reaction, t1/2 = 1/(k[A]0), which depends on the initial concentration.
Q121 mcq
The two functional groups characteristic of sugars are
a.
carbonyl and hydroxyl Correct Answer
b.
hydroxyl and methyl
c.
carbonyl and phosphate
d.
carbonyl and methyl
Step-by-Step AI Explanation
Verified Method
Sugars (carbohydrates) are polyhydroxy aldehydes or polyhydroxy ketones, containing hydroxyl (-OH) and carbonyl (>C=O) groups.
Q137 mcq
Which of the following compounds can form a zwitterion ?
a.
Glycine Correct Answer
b.
Aniline
c.
Benzoic acid
d.
Acetanilide
Step-by-Step AI Explanation
Verified Method
Glycine is an amino acid containing both an amino group and a carboxylic acid group, allowing it to form a zwitterion in aqueous solution.
Q138 mcq
The geometry and magnetic behaviour of the complex [Ni(CO)4] are
a.
tetrahedral geometry and paramagnetic
b.
square planar geometry and diamagnetic
c.
square planar geometry and paramagnetic
d.
tetrahedral geometry and diamagnetic Correct Answer
Step-by-Step AI Explanation
Verified Method
[Ni(CO)4] is a tetrahedral complex. Ni is in the 0 oxidation state (3d8 4s2). CO is a strong field ligand, causing all electrons to pair up, resulting in a diamagnetic complex.
Q139 mcq
Iron carbonyl, Fe(CO)5 is
a.
dinuclear
b.
tetranuclear
c.
trinuclear
d.
mononuclear Correct Answer
Step-by-Step AI Explanation
Verified Method
Fe(CO)5 contains only one iron atom, therefore it is a mononuclear carbonyl.
Q141 mcq
The type of isomerism shown by the complex [CoCl2(en)2] is
a.
Linkage isomerism
b.
Geometrical isomerism Correct Answer
c.
Ionization isomerism
d.
Coordination isomerism
Step-by-Step AI Explanation
Verified Method
[CoCl2(en)2] shows geometrical isomerism in the form of cis and trans isomers.
Q143 mcq
Which of the following molecules represents the order of hybridisation sp2, sp2, sp, sp from left to right atoms?
a.
CH3 – CH = CH – CH3
b.
HC ≡ C – C ≡ CH
c.
CH2 = CH – CH = CH2
d.
CH2 = CH – C ≡ CH Correct Answer
Step-by-Step AI Explanation
Verified Method
In CH2 = CH – C ≡ CH, the carbons from left to right have hybridizations: sp2, sp2, sp, sp.
Q143 mcq
Which of the following molecules represents the order of hybridisation sp2, sp2, sp, sp from left to right atoms ?
a.
CH3 – CH = CH – CH3
b.
HC ≡ C – C ≡ CH
c.
CH2 = CH – CH = CH2
d.
CH2 = CH – C ≡ CH Correct Answer
Step-by-Step AI Explanation
Verified Method
In CH2=CH-C≡CH, the carbons are sp2 (terminal), sp2, sp, and sp (terminal), fitting the requested sequence from left to right.
Q145 mcq
Which of the following is correct with respect to – I effect of the substituents? (R = alkyl)
a.
– NR2 > – OR > – F
b.
– NH2 < – OR < – F Correct Answer
c.
– NH2 > – OR > – F
d.
– NR2 < – OR < – F
Step-by-Step AI Explanation
Verified Method
The electron-withdrawing inductive effect (-I) is determined by electronegativity. Fluorine is the most electronegative, followed by Oxygen, then Nitrogen.
Q145 mcq
Which of the following is correct with respect to – I effect of the substituents ? (R = alkyl)
a.
– NR2 > – OR > – F
b.
– NH2 < – OR < – F Correct Answer
c.
– NH2 > – OR > – F
d.
– NR2 < – OR < – F
Step-by-Step AI Explanation
Verified Method
The inductive effect (-I) depends on electronegativity. F is the most electronegative, followed by O (in OR), and then N (in NH2/NR2). Therefore, the magnitude of the -I effect is F > OR > NH2.
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Q146 mcq
The solubility of BaSO4 in water is 2·42 × 10–3 gL–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol–1)
a.
1·08 × 10–8 mol2 L–2
b.
1·08 × 10–10 mol2 L–2
c.
1·08 × 10–14 mol2 L–2
d.
1·08 × 10–12 mol2 L–2
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Q146 mcq
The solubility of BaSO4 in water is 2.42 × 10^-3 gL^-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol^-1)
a.
1.08 × 10^-8 mol^2 L^-2
b.
1.08 × 10^-10 mol^2 L^-2
c.
1.08 × 10^-14 mol^2 L^-2
d.
1.08 × 10^-12 mol^2 L^-2
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Q150 mcq
Which of the following statements is not true for halogens?
a.
Chlorine has the highest electron-gain enthalpy.
b.
All form monobasic oxyacids.
c.
All but fluorine show positive oxidation states.
d.
All are oxidizing agents.
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Q151 mcq
Considering Ellingham diagram, which of the following metals can be used to reduce alumina?
a.
Cu
b.
Fe
c.
Mg
d.
Zn
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Q152 mcq
The correct order of atomic radii in group 13 elements is
a.
B < Ga < Al < In < Tl
b.
B < Al < In < Ga < Tl
c.
B < Ga < Al < Tl < In
d.
B < Al < Ga < In < Tl
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Q153 mcq
In the structure of ClF3, the number of lone pairs of electrons on central atom ‘Cl’ is
a.
three
b.
one
c.
four
d.
two
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Q154 mcq
The correct order of N-compounds in its decreasing order of oxidation states is
a.
NH4Cl, N2, NO, HNO3
b.
HNO3, NO, N2, NH4Cl
c.
HNO3, NH4Cl, NO, N2
d.
HNO3, NO, NH4Cl, N2
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Q155 mcq
Which one of the following elements is unable to form –3 6 MF ion?
a.
In
b.
Ga
c.
B
d.
Al
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Q156 mcq
The compound A on treatment with Na gives B, and with PCl5 gives C. B and C react together to give diethyl ether. A, B and C are in the order
a.
C2H5OH, C2H5ONa, C2H5Cl
b.
C2H5OH, C2H6, C2H5Cl
c.
C2H5Cl, C2H6, C2H5OH
d.
C2H5OH, C2H5Cl, C2H5ONa
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Q157 mcq
Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH4
b.
CH ≡ CH
c.
CH3 – CH3
d.
CH2 = CH2
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Q160 mcq
The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
b.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
c.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
d.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
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Q161 mcq
Among CaH2, BeH2, BaH2, the order of ionic character is
a.
BaH2 < BeH2 < CaH2
b.
BeH2 < CaH2 < BaH2
c.
BeH2 < BaH2 < CaH2
d.
CaH2 < BeH2 < BaH2
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Q161 mcq
Among CaH2, BeH2, BaH2, the order of ionic character is
a.
BaH2 < BeH2 < CaH2
b.
BeH2 < CaH2 < BaH2
c.
BeH2 < BaH2 < CaH2
d.
CaH2 < BeH2 < BaH2
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Q163 mcq
In which case is the number of molecules of water maximum?
a.
10^-3 mol of water
b.
18 mL of water
c.
0.00224 L of water vapours at 1 atm and 273 K
d.
0.18 g of water
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Q164 mcq
Carboxylic acids have higher boiling points than aldehydes, ketones and even alcohols of comparable molecular mass. It is due to their
a.
formation of intermolecular H-bonding
b.
formation of intramolecular H-bonding
c.
more extensive association of carboxylic acid via van der Waals force of attraction
d.
formation of carboxylate ion
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Q166 mcq
In the reaction [Reimer-Tiemann], the electrophile involved is
a.
dichlorocarbene (:CCl2)
b.
dichloromethyl cation (CHCl2+)
c.
dichloromethyl anion (CHCl2-)
d.
formyl cation (CHO+)
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Q167 mcq
The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is – 200 kJ mol^-1. The bond dissociation energy of X2 will be
a.
400 kJ mol^-1
b.
200 kJ mol^-1
c.
800 kJ mol^-1
d.
100 kJ mol^-1
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Q168 mcq
When initial concentration of the reactant is doubled, the half-life period of a zero order reaction
a.
remains unchanged
b.
is halved
c.
is tripled
d.
is doubled
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Q173 mcq
Nitration of aniline in strong acidic medium also gives m-nitroaniline because
a.
In acidic (strong) medium aniline is present as anilinium ion.
b.
In spite of substituents nitro group always goes to only m-position.
c.
In absence of substituents nitro group always goes to m-position.
d.
In electrophilic substitution reactions amino group is meta directive.
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Q174 mcq
Which of the following oxides is most acidic in nature?
a.
CaO
b.
MgO
c.
BaO
d.
BeO
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Q174 mcq
Which of the following oxides is most acidic in nature?
a.
CaO
b.
MgO
c.
BaO
d.
BeO
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Q175 mcq
The difference between amylose and amylopectin is
a.
Amylose is made up of glucose and galactose
b.
Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 alpha-linkage
c.
Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
d.
Amylose have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
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Q175 mcq
The difference between amylose and amylopectin is
a.
Amylose is made up of glucose and galactose
b.
Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 alpha-linkage
c.
Amylopectin have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
d.
Amylose have 1 -> 4 alpha-linkage and 1 -> 6 beta-linkage
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Q176 mcq
A mixture of 2.3 g formic acid (HCOOH) and 4.5 g oxalic acid (H2C2O4) is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
a.
4.4
b.
1.4
c.
2.8
d.
3.0
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Q177 mcq
Which one is a wrong statement?
a.
The value of m for 2pz orbital is zero.
b.
Total orbital angular momentum of electron in ‘s’ orbital is equal to zero.
c.
The electronic configuration of N atom is [He] 2s2 2p3.
d.
An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
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Q177 mcq
Which one is a wrong statement?
a.
The value of m for 2pz is zero.
b.
Total orbital angular momentum of electron in ‘s’ orbital is equal to zero.
c.
The electronic configuration of N atom is [He] 2s2 2p3.
d.
An orbital is designated by three quantum numbers while an electron in an atom is designated by four quantum numbers.
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Q178 mcq
Consider the following species : CN+, CN–, NO and CN. Which one of these will have the highest bond order?
a.
CN
b.
NO
c.
CN+
d.
CN-
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Q179 mcq
Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is
a.
Mg3X2
b.
Mg2X3
c.
Mg2X
d.
MgX2
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