The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
b.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
c.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
d.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
Correct Answer
Step-by-Step AI Explanation
Verified Method
For a first-order reaction, t1/2 = ln2/k (independent of concentration). For a second-order reaction, t1/2 = 1/(k[A]0), which depends on the initial concentration.
Q121mcq
The two functional groups characteristic of sugars are
a.
carbonyl and hydroxyl
Correct Answer
b.
hydroxyl and methyl
c.
carbonyl and phosphate
d.
carbonyl and methyl
Step-by-Step AI Explanation
Verified Method
Sugars (carbohydrates) are polyhydroxy aldehydes or polyhydroxy ketones, containing hydroxyl (-OH) and carbonyl (>C=O) groups.
Q137mcq
Which of the following compounds can form a zwitterion ?
a.
Glycine
Correct Answer
b.
Aniline
c.
Benzoic acid
d.
Acetanilide
Step-by-Step AI Explanation
Verified Method
Glycine is an amino acid containing both an amino group and a carboxylic acid group, allowing it to form a zwitterion in aqueous solution.
Q138mcq
The geometry and magnetic behaviour of the complex [Ni(CO)4] are
a.
tetrahedral geometry and paramagnetic
b.
square planar geometry and diamagnetic
c.
square planar geometry and paramagnetic
d.
tetrahedral geometry and diamagnetic
Correct Answer
Step-by-Step AI Explanation
Verified Method
[Ni(CO)4] is a tetrahedral complex. Ni is in the 0 oxidation state (3d8 4s2). CO is a strong field ligand, causing all electrons to pair up, resulting in a diamagnetic complex.
Q139mcq
Iron carbonyl, Fe(CO)5 is
a.
dinuclear
b.
tetranuclear
c.
trinuclear
d.
mononuclear
Correct Answer
Step-by-Step AI Explanation
Verified Method
Fe(CO)5 contains only one iron atom, therefore it is a mononuclear carbonyl.
Q141mcq
The type of isomerism shown by the complex [CoCl2(en)2] is
a.
Linkage isomerism
b.
Geometrical isomerism
Correct Answer
c.
Ionization isomerism
d.
Coordination isomerism
Step-by-Step AI Explanation
Verified Method
[CoCl2(en)2] shows geometrical isomerism in the form of cis and trans isomers.
Q143mcq
Which of the following molecules represents the order of hybridisation sp2, sp2, sp, sp from left to right atoms?
a.
CH3 – CH = CH – CH3
b.
HC ≡ C – C ≡ CH
c.
CH2 = CH – CH = CH2
d.
CH2 = CH – C ≡ CH
Correct Answer
Step-by-Step AI Explanation
Verified Method
In CH2 = CH – C ≡ CH, the carbons from left to right have hybridizations: sp2, sp2, sp, sp.
Q143mcq
Which of the following molecules represents the order of hybridisation sp2, sp2, sp, sp from left to right atoms ?
a.
CH3 – CH = CH – CH3
b.
HC ≡ C – C ≡ CH
c.
CH2 = CH – CH = CH2
d.
CH2 = CH – C ≡ CH
Correct Answer
Step-by-Step AI Explanation
Verified Method
In CH2=CH-C≡CH, the carbons are sp2 (terminal), sp2, sp, and sp (terminal), fitting the requested sequence from left to right.
Q145mcq
Which of the following is correct with respect to – I effect of the substituents? (R = alkyl)
a.
– NR2 > – OR > – F
b.
– NH2 < – OR < – F
Correct Answer
c.
– NH2 > – OR > – F
d.
– NR2 < – OR < – F
Step-by-Step AI Explanation
Verified Method
The electron-withdrawing inductive effect (-I) is determined by electronegativity. Fluorine is the most electronegative, followed by Oxygen, then Nitrogen.
Q145mcq
Which of the following is correct with respect to – I effect of the substituents ? (R = alkyl)
a.
– NR2 > – OR > – F
b.
– NH2 < – OR < – F
Correct Answer
c.
– NH2 > – OR > – F
d.
– NR2 < – OR < – F
Step-by-Step AI Explanation
Verified Method
The inductive effect (-I) depends on electronegativity. F is the most electronegative, followed by O (in OR), and then N (in NH2/NR2). Therefore, the magnitude of the -I effect is F > OR > NH2.
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The solubility of BaSO4 in water is 2·42 × 10–3 gL–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol–1)
a.
1·08 × 10–8 mol2 L–2
b.
1·08 × 10–10 mol2 L–2
c.
1·08 × 10–14 mol2 L–2
d.
1·08 × 10–12 mol2 L–2
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The solubility of BaSO4 in water is 2.42 × 10^-3 gL^-1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol^-1)
a.
1.08 × 10^-8 mol^2 L^-2
b.
1.08 × 10^-10 mol^2 L^-2
c.
1.08 × 10^-14 mol^2 L^-2
d.
1.08 × 10^-12 mol^2 L^-2
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Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH4
b.
CH ≡ CH
c.
CH3 – CH3
d.
CH2 = CH2
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The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
b.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
c.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
d.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
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The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is – 200 kJ mol^-1. The bond dissociation energy of X2 will be
a.
400 kJ mol^-1
b.
200 kJ mol^-1
c.
800 kJ mol^-1
d.
100 kJ mol^-1
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A mixture of 2.3 g formic acid (HCOOH) and 4.5 g oxalic acid (H2C2O4) is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
a.
4.4
b.
1.4
c.
2.8
d.
3.0
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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is
a.
Mg3X2
b.
Mg2X3
c.
Mg2X
d.
MgX2
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