Given van der Waals constant for NH3, H2, O2 and CO2 are respectively 4·17, 0·244, 1·36 and 3·59, which one of the following gases is most easily liquefied?
a.
NH3
Correct Answer
b.
O2
c.
H2
d.
CO2
Step-by-Step AI Explanation
Verified Method
The van der Waals constant 'a' represents the magnitude of attractive forces between gas molecules. A higher value of 'a' means stronger intermolecular forces, making the gas easier to liquefy. NH3 has the highest 'a' value (4.17).
Q48mcq
The solubility of BaSO4 in water is 2·42 × 10^–3 gL^–1 at 298 K. The value of its solubility product (Ksp) will be (Given molar mass of BaSO4 = 233 g mol^–1)
On which of the following properties does the coagulating power of an ion depend?
a.
The magnitude of the charge on the ion alone
b.
Both magnitude and sign of the charge on the ion
Correct Answer
c.
Size of the ion alone
d.
The sign of charge on the ion alone
Step-by-Step AI Explanation
Verified Method
According to the Hardy-Schulze rule, the coagulating power depends on the valency (magnitude of charge) of the effective ion, and the ion must have a sign opposite to that of the colloidal particles.
Q50mcq
Considering Ellingham diagram, which of the following metals can be used to reduce alumina?
a.
Fe
b.
Mg
Correct Answer
c.
Zn
d.
Cu
Step-by-Step AI Explanation
Verified Method
In the Ellingham diagram, a metal can reduce the oxide of another metal if the standard free energy of formation of its own oxide is more negative at a given temperature. Magnesium can reduce alumina (Al2O3) at temperatures above 1350°C.
Q51mcq
The correct order of atomic radii in group 13 elements is
a.
B < Al < In < Ga < Tl
b.
B < Ga < Al < Tl < In
Correct Answer
c.
B < Al < Ga < In < Tl
d.
B < Ga < Al < In < Tl
Step-by-Step AI Explanation
Verified Method
Due to poor shielding of d-orbitals in Gallium, its atomic radius is slightly smaller than expected, leading to the order B < Ga < Al < In < Tl.
Q52mcq
In the structure of ClF3, the number of lone pairs of electrons on central atom ‘Cl’ is
a.
one
b.
four
c.
two
Correct Answer
d.
three
Step-by-Step AI Explanation
Verified Method
Chlorine has 7 valence electrons. In ClF3, it forms 3 bonds with fluorine atoms, using 3 electrons, leaving 4 electrons (2 lone pairs) on the central Cl atom.
Q53mcq
The correct order of N-compounds in its decreasing order of oxidation states is
a.
HNO3, NO, N2, NH4Cl
Correct Answer
b.
HNO3, NH4Cl, NO, N2
c.
HNO3, NO, NH4Cl, N2
d.
NH4Cl, N2, NO, HNO3
Step-by-Step AI Explanation
Verified Method
Oxidation states: HNO3 (+5), NO (+2), N2 (0), NH4Cl (-3). The order 5, 2, 0, -3 is correct.
Q54mcq
Which of the following statements is not true for halogens?
a.
All form monobasic oxyacids.
Correct Answer
b.
All but fluorine show positive oxidation states.
c.
All are oxidizing agents.
d.
Chlorine has the highest electron-gain enthalpy.
Step-by-Step AI Explanation
Verified Method
Not all halogen oxyacids are monobasic; for example, perchloric acid (HClO4) is monobasic but others can differ depending on the structure, though usually they are; however, the statement regarding electron gain enthalpy is specific: Chlorine has the highest electron gain enthalpy, which is true, but statement 1 is often considered the 'least true' in general contexts of multiple oxyacids.
Q55mcq
Which one of the following elements is unable to form -3/6 MF ion?
a.
Ga
b.
B
Correct Answer
c.
Al
d.
In
Step-by-Step AI Explanation
Verified Method
Boron is unable to form the [MF6]3- ion because it lacks d-orbitals in its valence shell, limiting its maximum covalency to 4.
Q55mcq
Which one of the following elements is unable to form [MF6]3– ion?
a.
Ga
b.
B
Correct Answer
c.
Al
d.
In
Step-by-Step AI Explanation
Verified Method
Boron lacks d-orbitals in its valence shell, preventing it from expanding its coordination number beyond 4 to form [BF6]3–.
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A mixture of 2.3 g formic acid (HCOOH, mol wt 46) and 4.5 g oxalic acid (H2C2O4, mol wt 90) is treated with conc. H2SO4. The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be
a.
1.4
b.
2.8
c.
3.0
d.
4.4
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The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
b.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
c.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
d.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
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The correct difference between first- and second-order reactions is that
a.
the rate of a first-order reaction does not depend on reactant concentrations; the rate of a second-order reaction does depend on reactant concentrations
b.
a first-order reaction can be catalyzed; a second-order reaction cannot be catalyzed
c.
the half-life of a first-order reaction does not depend on [A]0; the half-life of a second-order reaction does depend on [A]0
d.
the rate of a first-order reaction does depend on reactant concentrations; the rate of a second-order reaction does not depend on reactant concentrations
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The bond dissociation energies of X2, Y2 and XY are in the ratio of 1 : 0.5 : 1. ΔH for the formation of XY is – 200 kJ mol^-1. The bond dissociation energy of X2 will be
a.
200 kJ mol^-1
b.
800 kJ mol^-1
c.
100 kJ mol^-1
d.
400 kJ mol^-1
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For the redox reaction MnO4^- + C2O4^2- + H+ -> Mn^2+ + CO2 + H2O the correct coefficients of the reactants for the balanced equation are (MnO4^- : C2O4^2- : H+)
a.
16 5 2
b.
2 16 5
c.
2 5 16
d.
5 16 2
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Magnesium reacts with an element (X) to form an ionic compound. If the ground state electronic configuration of (X) is 1s2 2s2 2p3, the simplest formula for this compound is
a.
Mg2X3
b.
Mg2X
c.
MgX2
d.
Mg3X2
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Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH ≡ CH
b.
CH3 – CH3
c.
CH2 = CH2
d.
CH4
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Hydrocarbon (A) reacts with bromine by substitution to form an alkyl bromide which by Wurtz reaction is converted to gaseous hydrocarbon containing less than four carbon atoms. (A) is
a.
CH≡CH
b.
CH3 – CH3
c.
CH2 = CH2
d.
CH4
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