According to crystal field theory, $\text{Ni}^{2+}$ can have two unpaired electrons in
a.
Octahedral geometry only
b.
Square-planar geometry only
c.
Tetrahedral geometry only
d.
Both octahedral and tetrahedral geometry.
Correct Answer
Step-by-Step AI Explanation
Verified Method
$ ext{Ni}^{2+}$ has a $d^8$ electronic configuration.
- In an octahedral field, the splitting gives $t_{2g}^6 e_g^2$, which has $2$ unpaired electrons regardless of ligand field strength.
- In a tetrahedral field, the splitting gives $e^4 t_2^4$, which also has $2$ unpaired electrons according to Hund's rule.
- In a square-planar geometry, low-spin configuration is favored, resulting in all $8$ electrons being paired (diamagnetic, $0$ unpaired electrons).
Therefore, $ ext{Ni}^{2+}$ has two unpaired electrons in both octahedral and tetrahedral geometries.
Q22mcq
$[\text{Ni}(\text{CN})_4]^{2-}$ and $[\text{NiCl}_4]^{2-}$ complex ions are
a.
Both diamagnetic
b.
Both paramagnetic
c.
Diamagnetic and paramagnetic respectively
Correct Answer
d.
Antiferromagnetic and diamagnetic respectively
Step-by-Step AI Explanation
Verified Method
In $[ ext{Ni}( ext{CN})_4]^{2-}$, $ ext{Ni}^{2+}$ is a $d^8$ ion with $ ext{CN}^-$ as a strong-field ligand, resulting in a square-planar, low-spin complex ($dsp^2$) with no unpaired electrons ($n = 0$), making it diamagnetic.
In $[ ext{NiCl}_4]^{2-}$, $ ext{Cl}^-$ is a weak-field ligand, giving a tetrahedral complex ($sp^3$) with configuration $e^4 t_2^4$, which has two unpaired electrons ($n = 2$), making it paramagnetic.
Thus, the complexes are diamagnetic and paramagnetic, respectively.
Q23mcq
Which of the following spectroscopic techniques will be useful to distinguish between M-SCN and M-NCS binding modes?
a.
NMR
b.
IR
Correct Answer
c.
EPR
d.
Mass
Step-by-Step AI Explanation
Verified Method
Infrared (IR) spectroscopy is the classic and most effective technique for distinguishing between linkage isomers involving thiocyanate ($-\text{SCN}^-$) and isothiocyanate ($-\text{NCS}^-$) ligands:
- The $\text{C-N}$ stretching frequency, $\nu(\text{CN})$, occurs at higher wavenumbers for S-bonded complexes (typically above $2100\text{ cm}^{-1}$, often sharp) compared to N-bonded complexes (typically below $2100\text{ cm}^{-1}$, usually broad and intense).
- More definitively, the $\nu(\text{CS})$ stretching frequency appears around $780 - 860\text{ cm}^{-1}$ for M-NCS and down around $690 - 720\text{ cm}^{-1}$ for M-SCN.
- The $\delta(\text{NCS})$ bending modes also show characteristic differences (around $470 - 490\text{ cm}^{-1}$ for N-bonded vs. $410 - 440\text{ cm}^{-1}$ for S-bonded).
Therefore, IR spectroscopy (Option B) is the technique used to distinguish between these binding modes.
Q24mcq
Which of the following compound show a charge-transfer band?
a.
Lanthanum nitrate
b.
Ceric ammonium nitrate
Correct Answer
c.
Manganese (II) acetate
d.
Copper (II) sulphate pentahydrate
Step-by-Step AI Explanation
Verified Method
Ceric ammonium nitrate contains $\text{Ce}^{4+}$, which has a noble-gas $4f^0$ configuration. Because it has no $d$ or $f$ electrons, it cannot undergo $d-d$ or $f-f$ transitions. Its intense orange-yellow color arises from a Ligand-to-Metal Charge Transfer (LMCT) transition from the nitrate ligands to the empty $\text{Ce}^{4+}$ orbitals.
Q25mcq
Among $\text{SF}_4, \text{BF}_4^-, \text{XeF}_4$ and $\text{ICl}_4^-$ the number of species having two lone pair of electrons on the central atom according to VSEPR theory is:
a.
2
Correct Answer
b.
3
c.
4
d.
0
Step-by-Step AI Explanation
Verified Method
Using VSEPR theory to find the number of lone pairs ($lp$) on the central atom:
- $\text{SF}_4$: Sulfur has 6 valence electrons; forms 4 single bonds $\implies lp = (6 - 4)/2 = 1$ lone pair.
- $\text{BF}_4^-$: Boron has 3 valence electrons $+ 1$ negative charge $= 4$; forms 4 single bonds $\implies lp = (4 - 4)/2 = 0$ lone pairs.
- $\text{XeF}_4$: Xenon has 8 valence electrons; forms 4 single bonds $\implies lp = (8 - 4)/2 = 2$ lone pairs.
- $\text{ICl}_4^-$: Iodine has 7 valence electrons $+ 1$ negative charge $= 8$; forms 4 single bonds $\implies lp = (8 - 4)/2 = 2$ lone pairs.
Thus, only $\text{XeF}_4$ and $\text{ICl}_4^-$ have 2 lone pairs of electrons, making a total of 2 species.
Q26mcq
The FALSE statement for a polarographic measurement procedure is:
a.
$\text{O}_2$ is removed
b.
Dropping mercury electrode is working electrode.
c.
$\text{I}_d$ is proportionaal to concentation of electroactive species.
d.
Residual current is made zero by adding supporting electrolyte.
Correct Answer
Step-by-Step AI Explanation
Verified Method
Statement D is false. The addition of an excess of supporting electrolyte eliminates the migration current (by carrying nearly all the charge through the solution), not the residual current. The residual current consists of the faradaic current from trace impurities and the charging (capacitive) current of the mercury drop, which cannot be eliminated merely by adding supporting electrolyte.
Q27mcq
The ligand system present in vitamin $\text{B}_{12}$ is:
a.
Porphyrin
b.
Corrin
Correct Answer
c.
Phthalocyanine
d.
Crown ether
Step-by-Step AI Explanation
Verified Method
Vitamin $\text{B}_{12}$ (cobalamin) contains a cobalt ion coordinated to a corrin ring, a macrocyclic ligand structurally related to porphyrin but lacking one of the methine bridges, making it more flexible and directly linking two pyrrole rings.
Q28mcq
Which one of the following exhibits rotational spectra?
a.
$\text{H}_2$
b.
$\text{N}_2$
c.
$\text{CO}$
Correct Answer
d.
$\text{CO}_2$
Step-by-Step AI Explanation
Verified Method
For a molecule to exhibit a pure rotational spectrum in the microwave region, it must possess a permanent electric dipole moment (gross selection rule: $\mu \neq 0$).
- $\text{H}_2$ and $\text{N}_2$ are homonuclear diatomic molecules and have $\mu = 0$.
- $\text{CO}_2$ is a linear, centrosymmetric molecule and has $\mu = 0$.
- $\text{CO}$ is a heteronuclear diatomic molecule with a permanent dipole moment ($\mu \neq 0$), so it exhibits a pure rotational spectrum.
Q29mcq
In Ziegler-Natta catalysis the commonly used catalyst system is:
The traditional heterogeneous Ziegler-Natta catalyst system consists of a transition metal halide, most commonly titanium tetrachloride ($\text{TiCl}_4$) or titanium trichloride ($\text{TiCl}_3$), combined with an organoaluminum co-catalyst such as triethylaluminum, $\text{Al}(\text{C}_2\text{H}_5)_3$.
Cobaltocene, $(\eta^5-\text{C}_5\text{H}_5)_2\text{Co}$, is a 19-electron complex with an electron in an antibonding $e_{1g}^*$ orbital. It readily undergoes one-electron oxidation to form the very stable, 18-electron cobaltocenium cation, $[(\eta^5-\text{C}_5\text{H}_5)_2\text{Co}]^+$. In contrast, ferrocene and ruthenocene are already stable 18-electron complexes.
🎉 10 Free Sample Solutions Completed
Unlock All 125 Questions & Solutions
Sign up free in seconds to unlock step-by-step AI answers for the remaining 115 questions.
In a chemical reaction, $\mathrm{A(s)} + \mathrm{B(g)} \rightleftharpoons \mathrm{C(g)}$, the total pressure at equilibrium is $6\text{ atm}$. The value of equilibrium constant is:
a.
$1/2$
b.
$9$
c.
$1$
d.
$36$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
A molecule, AX, has a vibrational energy of $1000\text{ cm}^{-1}$ and rotational energy of $10\text{ cm}^{-1}$. Another molecule, BX, has a vibrational energy of $400\text{ cm}^{-1}$ and rotational energy of $40\text{ cm}^{-1}$. Which one of the following statements about the coupling of vibrational and rotational motion is true?
a.
The coupling is stronger in BX.
b.
The coupling is stronger in AX.
c.
Magnitude of coupling is same in both AX and BX.
d.
There is no coupling in both AX and BX
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The normalized hydrogen atom 1s wavefunction is given by $\Psi_{1\text{s}} = \frac{1}{\sqrt{\pi}}\left(\frac{\zeta}{a_0}\right)^{3/2} e^{-\zeta r/a_0}$ where $\zeta = 1$ and energy is $-0.5\text{ au}$. If we use a normalized wavefunction of the above form with $\zeta \neq 1$, the average value of energy of the ground state of hydrogen atom is:
a.
Greater than $-0.5\text{ au}$
b.
Equal to $-0.5\text{ au}$
c.
Less than $-0.5\text{ au}$
d.
Equal to $\zeta\text{ times} -0.5\text{ au}$.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Among the following statements, identify the correct ones for complexes of lanthanide(III) ion.
(A) Metal-ligand bond is significantly ionic.
(B) Complexes rarely show isomerism.
(C) The coordination number is not more than 8.
(D) The magnetic moments are not accounted even approximately by spin only value for majority of lanthanides.
a.
A, B and D only
b.
A, B and C only
c.
B and C only
d.
A and D only.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Identify the order according to increasing stability of the following organometallic compounds, $\text{TiMe}_4$, $\text{Ti}(\text{CH}_2\text{Ph})_4$, $\text{Ti}(\text{i-Pr})_4$ and $\text{TiEt}_4$.
$(\text{Me} = \text{methyl}, \text{Ph} = \text{phenyl}, \text{i-Pr} = \text{isopropyl}, \text{Et} = \text{ethyl})$
Given,
$$\text{Ag}^+ + \text{e} \rightarrow \text{Ag}, \quad \text{E}_0 = 0.50\text{ V}$$
$$\text{Cu}^{2+} + 2\text{e} \rightarrow \text{Cu}, \quad \text{E}_0 = 0.34\text{ V}$$
A $100\text{ ml}$ solution is $1080\text{ mg}$ with respect to $\text{Ag}^+$ and $635\text{ mg}$ with respect to $\text{Cu}^{2+}$. If $0.1\text{mg } \text{Ag}^+$ left in the solution is considered to be the complete deposition of $\text{Ag}^+$, the cathode potential, so that no copper is deposited during the process, is:
a.
$0.16\text{ V}$
b.
$0.84\text{ V}$
c.
$0.31\text{ V}$
d.
$-0.16\text{ V}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Consider two redox pairs
(1) $\mathrm{Cr(II)/Ru(III)}$
(2) $\mathrm{Cr(II)/Co(III)}$
The rate of acceleration in going from a outer-sphere to a inner-sphere mechanism is lower for (1) relative to (2). Its correct explanation is:
a.
HOMO/LUMO are $\sigma^*$ and $\sigma^*$ respectively.
b.
HOMO/LUMO are $\sigma^*$ and $\pi^*$ respectively.
c.
HOMO/LUMO are $\pi^*$ and $\sigma^*$ respectively.
d.
HOMO/LUMO are $\pi^*$ and $\pi^*$ respectively.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The correct value of isomer shift (in Mossbauer spectra) and its explanation for $\mathrm{Fe(II)-TPP}$ and $\mathrm{Fe(III)-TPP}$ respectively from the following are:
(TPP = tetraphenylporphyrinate)
(A) $0.52\text{ mms}^{-1}$
(B) $0.45\text{ mms}^{-1}$
(C) Increase in s electron density
(D) Decrease in s electron density.
a.
(A) and (D); (B) and (C)
b.
(A) and (C); (B) and (C)
c.
(B) and (D); (A) and (D)
d.
(B) and (D); (A) and (C)
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
In IR spectrum of $[\mathrm{Co(CN)_5H}]^{3-}$ the $\mathrm{Co-H}$ stretch is observed at $1840\text{ cm}^{-1}$. The $(\mathrm{Co-D})$ stretch in $[\mathrm{Co(CN)_5D}]^{3-}$ will appear at nearly
a.
$1300\text{ cm}^{-1}$
b.
$1400\text{ cm}^{-1}$
c.
$1500\text{ cm}^{-1}$
d.
$1600\text{ cm}^{-1}$.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
For the complexes
(A) $[\mathrm{Ni(H_2O)_6}]^{2+}$ (B) $[\mathrm{Mn(H_2O)_6}]^{2+}$ (C) $[\mathrm{Cr(H_2O)_6}]^{3+}$ (D) $[\mathrm{Ti(H_2O)_6}]^{3+}$, the ideal octahedral geometry will not be observed in
a.
(A) and (D)
b.
(C) and (D)
c.
(B) only
d.
(D) only
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Among the following, the number of anhydrides of acids are
$\mathrm{CO}$, $\mathrm{NO}$, $\mathrm{N_2O}$, $\mathrm{B_2O_3}$, $\mathrm{N_2O_5}$, $\mathrm{SO_3}$ and $\mathrm{P_4O_{10}}$.
a.
3
b.
4
c.
5
d.
6
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
For a given nuclear fission reaction of $^{235}\text{U}$
$$^{235}_{92}\text{U} + {^1_0}\text{n} \longrightarrow {^{142}_{56}}\text{Ba} + {^{91}_{36}}\text{Kr} + 3{^1_0}\text{n}$$
the amount of energy (in $\text{kJ/mol}$) released during this process is (given $^{235}\text{U} = 235.0439\text{ amu}$, $^{142}\text{Ba} = 141.9164\text{ amu}$, $^{91}\text{Kr} = 90.9234\text{ amu}$, $\text{neutron} = 1.00866\text{ amu}$)
a.
$3.12 \times 10^{12}$
b.
$2.8 \times 10^{11}$
c.
$1.0 \times 10^9$
d.
$1.68 \times 10^{10}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The decomposition of gaseous acetaldehyde at $\text{T(K)}$ follows second order kinetics. The half-life of this reaction is $400\text{ s}$ when the initial pressure is $250\text{ Torr}$. What will be the rate constant (in $\text{Torr}^{-1}\text{ s}^{-1}$) and half-life (in $\text{s}$) respectively, if the initial pressure of the acetaldehyde is $200\text{ Torr}$ at the same temperature?
a.
$10^5$ and $500$
b.
$10^{-5}$ and $400$
c.
$10^{-4}$ and $400$
d.
$10^{-5}$ and $500$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
For an enzyme catalyzed reaction, a Lineweaver-Burk plot gave the following data:
$\text{slope} = 40\text{ s}$
$\text{intercept} = 4\text{ (mmol dm}^{-3}\text{ s}^{-1})^{-1}$.
If the initial concentration of enzyme is $2.5 \times 10^{-9}\text{ mol dm}^{-3}$, what is the catalytic efficiency (in $\text{dm}^3\text{ mol}^{-1}\text{ s}^{-1}$) of the reaction?
a.
$10^5$
b.
$10^6$
c.
$10^7$
d.
$10^4$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The unperturbed energy levels of a system are $\epsilon_0 = 0$, $\epsilon_1 = 2$ and $\epsilon_2 = 4$. The second order correction to energy for the ground state in pressure of the perturbation $\text{V}$ for which $\text{V}_{10} = 2$, $\text{V}_{20} = 4$ and $\text{V}_{12} = 6$ has been found to be
a.
$-6$
b.
$0$
c.
$+6$
d.
$-8$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The variation of equilibrium constant (K) of a certain reaction with temperature (T) is
$$\ln k = 3.0 + \frac{2.0 \times 10^4}{\text{T}}$$
given $\text{R} = 8.3\text{ Jk}^{-1}\text{mol}^{-1}$, the values of $\Delta\text{H}^0$ and $\Delta\text{S}^0$ are.
a.
$166\text{ kJ mol}^{-1}$ and $24.9\text{ Jk}^{-1}\text{ mol}^{-1}$.
b.
$166\text{ kJ mol}^{-1}$ and $-24.9\text{ Jk}^{-1}\text{ mol}^{-1}$
c.
$-166\text{ kJ mol}^{-1}$ and $24.9\text{ Jk}^{-1}\text{ mol}^{-1}$
d.
$-166\text{ kJ mol}^{-1}$ and $24.9\text{ Jk}^{-1}\text{ mol}^{-1}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The chemical potential of component 1 in a solution of binary mixture is $\mu_1 = \mu_1^0 + \text{RT}\ln \text{p}_1$, when $\text{p}_1$ is the partial pressure of component 1 vapour phase. The standard state $\mu_1^0$ is:
a.
Independent of temperature and pressure
b.
Depends on temperature and pressure both
c.
Depends on temperature only
d.
Depends on pressure only
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Debey-Hückel screening length ($\kappa^{-1}$) is a measure of size of diffuse ion cloud around an ion, provided $\sqrt{\frac{2\text{e}^2\text{N}_{\text{A}}}{\epsilon_0\text{ k}_{\text{B}}\text{T}}} \approx 30\left(\text{nm}\sqrt{\text{mol}\text{kg}^{-1}}\right)^{-1}$ at 298K, which of the following values of $\kappa^{-1}$ is true for a 0.03 molal solution for $\text{Na}_2\text{SO}_4$ in water ($\epsilon_{\text{r}} \approx 100$)?
a.
$\frac{10}{9}\text{ nm}$
b.
$\frac{9}{10}\text{ nm}$
c.
$\frac{10\sqrt{2}}{9}\text{ nm}$
d.
$\frac{9}{10\sqrt{2}}\text{ nm}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
If the ratio of composition of oxidized and reduced species in electrochemical cell, is given as $\frac{[\text{O}]}{[\text{R}]} = \text{e}^2$, the correct potential difference will be
If the equilibrium constants for the reactions 1 and 2
(1) $\text{CO}(\text{g}) + \text{H}_2\text{O}(\text{g}) \rightleftharpoons \text{CO}_2(\text{g}) + \text{H}_2(\text{g})$
(2) $\text{CH}_4(\text{g}) + \text{H}_2\text{O}(\text{g}) \rightleftharpoons \text{CO}(\text{g}) + 3\text{H}_2(\text{g})$
are $\text{k}_1$ and $\text{k}_2$, the equilibrium constant for the reaction
$$\text{CH}_4(\text{g}) + 2\text{H}_2\text{O}(\text{g}) \rightleftharpoons \text{CO}_2(\text{g}) + 4\text{H}_2(\text{g})$$
is:
a.
$\text{k}_1 + \text{k}_2$
b.
$\text{k}_1 - \text{k}_2$
c.
$\text{k}_1\text{k}_2$
d.
$\text{k}_1 / \text{k}_2$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The virial expansion for a real gas can be written in either of the following forms:
$$\frac{\text{P}\overline{\text{V}}}{\text{RT}} = 1 + \text{B}_{\text{p}}\text{P} + \text{C}_{\text{p}}\text{P}^2 + .....$$
$$= 1 + \text{B}_{\text{v}}\text{V} + \text{C}_{\text{v}}\text{V}^2 + .....$$
If $\text{B}_{\text{v}} = \alpha\text{B}_{\text{p}}$, the value of $\alpha$ would be
a.
$\text{PV/RT}$
b.
$\text{RT/PV}$
c.
$\text{PV}$
d.
$\text{RT}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
A certain system of noninteracting particles has the single-particle patition has the single-particle partition function $\text{f} = \text{A}\frac{\text{T}^\text{m}}{\text{V}}$ where $\text{A}$ is some constant. The average energy per particle will be
a.
$\text{m}\kappa\text{T}$
b.
$\text{A}\kappa\text{T}$
c.
$\kappa\text{T} / \text{m}$
d.
$\kappa\text{T} / \text{A}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Observe the following aqueous solutions of same compound. All the measurements are made at same wavelength and same temperature.
\textbf{Solution A:} The transmittance of $0.1\text{ mol dm}^{-3}$ using $1\text{ cm}$ cell is $0.5$.
\textbf{Solution B:} The optical density $0.5\text{ mol dm}^{-3}$ is measured using $1\text{ mm}$ cell.
\textbf{Solution C:} The transmittance of this solution is $0.1$.
The optical density of these solutions follow the order.
($\log 20 = 1.3010$; $\log 30 = 1.4771$, $\log 50 = 1.6990$
a.
$\text{A} > \text{B} > \text{C}$
b.
$\text{B} > \text{C} > \text{A}$
c.
$\text{B} > \text{A} > \text{C}$
d.
$\text{C} > \text{A} > \text{B}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The rotational constant of $^{14}\text{N}_2$ is $2\text{ cm}^{-1}$. The wave number of incident radiation in a Raman spectrometer is $20487\text{ cm}^{-1}$. What is the wave number of first scattered Stokes line (in $\text{cm}^{-1}$) of $^{14}\text{N}_2$?
a.
$20479$
b.
$20475$
c.
$20499$
d.
$20495$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
For a certain particle encountering a barrier, the tunneling probability is approximately $\text{e}^{-10}$. If the mass is halved and width of the barrier (rectangular) doubled, approximate value of the tunneling probability will be
a.
$\text{e}^{-10/\sqrt{2}}$
b.
$\text{e}^{-10\sqrt{2}}$
c.
$\text{e}^{-20\sqrt{2}}$
d.
$\text{e}^{-10}$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
A one-dimensional crystal of lattice dimension 'a' is metallic. If the structure is distorted in such a way that the lattice dimension is enhanced to '2a'.
a.
The electronic structure remains unchagned.
b.
The width of conduction band decreases and a band gap is generated.
c.
The width of conduction band increases
d.
The width of the conduction band remains unchanged.
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
For a $\text{H}_2$ molecule, the ground state wavefunction is $\psi(1,2) = \phi(1,2)\sigma(1,2)$ where $\phi$ refers to the space part and $\sigma$ to the spin part. Given that $\phi(1,2) = \phi(2,1)$, the form of $\sigma(1,2)$ would be
a.
$\alpha(1)\beta(2)$
b.
$\alpha(2)\beta(1)$
c.
$\alpha(1)\beta(2) - \alpha(2)\beta(1)$
d.
$\alpha(1)\beta(2) + \alpha(2)\beta(1)$
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
There are several types of mean molar masses for polymer and they are dependent on experimental methods like:
(1) Osmometry
(2) Light scattering
(3) Sedimentation.
Correct relation between mean molar masses and experimental method is:
An organic compound ($\text{C}_7\text{H}_{12}\text{O}_2$) exhibited the following data in the $^1\text{H}$ NMR spectrum.
$\delta$ 7.10 (1 H, d t, $J = 16$ and 7.2 Hz), 5.90 (1H, d t, $J = 16$ and 2 Hz),
4.1 (2H, q, $J = 7.2\text{ Hz}$), 2.10 (2H, m), 1.25 (3H, t, $J = 7.2\text{ Hz}$),
0.90 (3H, t, $J = 7.2\text{ Hz}$) ppm.
The compound, among the choices given below, is:
a.
(See image)
b.
(See image)
c.
(See image)
d.
(See image)
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The major compound X formed in the following reaction exhibited a strong absorption at $\nu_{\max} 1765\text{ cm}^{-1}$ in the IR spectrum. The structure of X is:
a.
(See image)
b.
(See image)
c.
(See image)
d.
(See image)
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
The gauche interaction values for Me/Me, Me/Br and Br/Br are 3.3, 0.8 and 3.0 kJ/mol, respectively. Among the following, the most stable conformation of 2, 3-dibromobutane is:
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Match the following:
\begin{tabular}{|l|l|}
\hline
\textbf{Column I} & \textbf{Column II} \\
\hline
A. Pyrrole & i. Pictet-Spengler \\
B. 1, 4-dihydropyridine & ii. Chichibabin \\
C. Isoquinoline & iii. Paal-Knorr \\
& iv. Hantzsch \\
\hline
\end{tabular}
a.
(A)-i (B)-ii (C)-iii
b.
(A)-ii (B)-iii (C)-iv
c.
(A)-iv (B)-i (C)-ii
d.
(A)-iii (B)-iv (C)-i
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
Consider the following reaction:
In an experiment, 1.99 g of bromide A on reaction with ethanolic potassium hydroxide gave 1.062 g of a mixture of the olefins B and C. If the ratio of olefins B:C formed is 2:1, the yields for their formation, respectively, are
a.
60 and 30%
b.
50 and 25%
c.
66 and 33%
d.
54 and 27%
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
An organic compound A ($\text{C}_8\text{H}_{16}\text{O}_2$) on treatment with an excess of methylmagnesium chloride generated two alcohols B and C, whereas reaction of A with lithium aluminium hydride generated only a single alcohol C. Compound B on treatment with an acid yielded an olefin ($\text{C}_6\text{H}_{12}$), which exhibited only a singlet at $\delta\, 1.6\text{ ppm}$ in the $^1\text{H}\text{ NMR}$ spectrum. The compound A is:
Correct Answer & Step-by-Step Solution Locked
Sign in free to reveal the correct answer and AI explanation for this question.
